Question

If a^2+b^2+c^2=2(b+c-a) then find the value of a+b+c​

Answer 1

Answer:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

=2(b+c-a)+2(ab+bc+ca)

=2(ab+bc+ca+b+c-a)

Answer 2

Answer:

2(ab+bc+ca+b+c-a)

Explanation:

(a+b+c)^=a^+b^+c^+2(ab+bc+ca)

2(b+c-a)+2(ab+bc+ca)

2(ab+bc+ca+b+c-a)