Question

If a^2+b^2+c^2= 20, and ab+ac+ac= 22, then calculate a+b+c.

Answer 1

hey your ans is here

_________

given:-

a2+b2+c2=20

Ab+BC+ca =22 ( incorrect in the question)

to find:-

a+b+c

now apply

(a+b+c)2=a2+b2+c2+2(Ab+BC+ca)

putting values

(a+b+c)2=20+2(22)

(a+b+c)2=20+44=64

a+b+c=√64=8

a+b+c=8

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Answer 2

Here is your answer!!!!!

=> (a+b+c)²= a²+b²+c²+2(ab+bc+ac)

a²+b²+c²= 20 (given)

ab+bc+ac= 22 (given)

Put these values on the formula,


=> (a+b+c)² = 20 +2(22)

=> (a+b+c)²= 20+44

=> (a+b+c)²= 64

Now to find a+b+c,

=> a+b+c = √64


=> a+b+c = 8



Hence, a+b+c = 8



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