Question

if a^2+b^2+c^2=20 and ab +bc+ ca =8 find the value of a+b+c​

Answer 1

Answer:

±6

Solution:

(a+b+c)² can be written as

a²+b²+c²+2(ab+bc+ca)

and we know the value of above terms so putting the values we get

20+2(8)=36

(a+b+c)²=36

a+b+c=√36

a+b+c=±6

Answer 2

Answer:

a+b+c = 6

Step-by-step explanation:

a²+b²+c²=20 , ab+bc+ac =8

a+b+c = x

(a+b+c)^2 = a²+b²+c²+2ab+2bc+2ac

(a+b+c)^2=20+2(8)                   ( substituting values for a²+b²+c and ab+bc+ac)

( a+b+c) ^ 2=20+16

(a+b+c)^2=36

a+b+c = 6

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