If a^2+b^2+c^2=25
0and ab+bc+ca=3 find a+b+c
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Step-by-step explanation:
Given that, a²+b²+c²= 250 and ab+bc+ca = 3
=> (a+b+c)² = a²+b²+c²+2(ab+bc+ca)
=> (a+b+c)² = 250+2(3)
=> (a+b+c)² = 256
=> (a+b+c) = √256
=> (a+b+c) = 16
Hence a+b+c = 16
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