If a^2+b^2+c^2=250 and ab+bc+ca=3 find the value of a+b+c
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Given :
a2+ b2 +c2 =250
ab+ bc+ ca =3
Using identity
(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc +2ca
= 250+ 2(3)
= 250+6
(a+b+c)^2 = 256
(a+b+c) = √256
(a+b+c) = 16
(mean 16 is in positive or negative)
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