Math, asked by hemantbansal2004, 11 months ago

If a^2+b^2+c^2=250 and ab+bc+ca=3 find the value of a+b+c

Answers

Answered by siri43991
10

Given :

a2+ b2 +c2 =250

ab+ bc+ ca =3

Using identity

(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc +2ca

= 250+ 2(3)

= 250+6

(a+b+c)^2 = 256

(a+b+c) = √256

(a+b+c) = 16

(mean 16 is in positive or negative)

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