Question

If a^2+b^2+c^2=280 ab+bc+ca=9/2
So find the value of (a+b+c)^3

Answer 1

The value of (a+b+c)^3 = 4913

Answer 2

◇ ∆nswer ◇

Superman : " I'm here to Help "

we know , ( a+b+c )^3 = a+b+c(a+b+c)^2

Know , (a+b+c)^2 = a^2+b^2+c^2+2(ab+BC+CA)

so , 280 + 9 =√289 = a+b+c = 17

so , (a+b+c=^3 = 17×17×17=4913

#SupermanINFINITY