If a^2+b^2+c^2=280 ab+bc+ca=9/2
So find the value of (a+b+c)^3
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The value of (a+b+c)^3 = 4913
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◇ ∆nswer ◇
Superman : " I'm here to Help "
we know , ( a+b+c )^3 = a+b+c(a+b+c)^2
Know , (a+b+c)^2 = a^2+b^2+c^2+2(ab+BC+CA)
so , 280 + 9 =√289 = a+b+c = 17
so , (a+b+c=^3 = 17×17×17=4913
#SupermanINFINITY
Superman : " I'm here to Help "
we know , ( a+b+c )^3 = a+b+c(a+b+c)^2
Know , (a+b+c)^2 = a^2+b^2+c^2+2(ab+BC+CA)
so , 280 + 9 =√289 = a+b+c = 17
so , (a+b+c=^3 = 17×17×17=4913
#SupermanINFINITY
SupermanINFINITY:
Where is my Red Underwear ??
oops
-flies away-
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