Question

if a^2+b^2+c^2=38, ab=15, bc=6, ac=10 then the value of a+b+c​

Answer 1

a² + b² + c² + 2 ( ab + bc + ca) = ( a + b + C)²

= 38 + 2× ( 15 + 6 + 10 ) = (a + b + C)²

= 38 + 62 = ( a + b + C)²

100 = a + b + C ²

a + b + C = 10

Answer 2

Answer:

the required solution is In the above image