Question

If a^2+ b^2+ c^2=38,ab=15, BC=6, ca=10, then find the value of a+b+c

Answer 1

Step-by-step explanation:

a² + b² + c² = 38

ab = 15 , bc = 6 , ca = 10

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

(a+b+c)² = 38 + 2(15)+2(6)+2(10)

= 38 + 30 + 12 + 20

= 100

(a+b+c) = 10