If a^2 + b^2 + c^2 = 40 and ab + bc + ca = 30 then find the value of a + b + c
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Given: a²+ b²+ c²= 40, ab + bc + ac = 30
Find: a + b + c
(a + b + c)² = a² + b² + c²+ 2ab + 2bc + 2ac
(a + b + c)² = 40+ 2(ab+bc+ac) [Substituting the value and applying distributive property]
(a + b + c)² = 40+ 2(30) [Substituting the value]
(a + b + c)² = 40 +60
(a + b + c)² = 100
Applying the square root both sides
√((a + b + c)²) = √(100)
a + b + c = 10 :
Answered by
2
Answer:
Given: a²+ b²+ c²= 40, ab + bc + ac = 30
Find: a + b + c
(a + b + c)² = a² + b² + c²+ 2ab + 2bc + 2ac
(a + b + c)² = 40+ 2(ab+bc+ac) [Substituting the value and applying distributive property]
(a + b + c)² = 40+ 2(30) [Substituting the value]
(a + b + c)² = 40 +60
(a + b + c)² = 100
Applying the square root both sides
√((a + b + c)²) = √(100)
a + b + c = 10 :
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