Question

If a^2+b^2+c^2= 48, ab+bc+ca=26 find a+b+c?​

Answer 1

Answer:

a+b+c = 10

Step-by-step explanation:

We know (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

=> a + b + c = √{ a² + b² + c² + 2(ab + bc + ca)} = √(48 + 2×26)

=> a + b + c = √(48 + 52) = √(100) = 10.

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Answer 2

Step-by-step explanation:

Formula,

(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca

⇒(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

Given,

ab+bc+ca=10,a

2

+b

2

+c

2

=16

⇒(a+b+c)

2

=16+2(10)

a+b+c=

16+20

=6