Question

If a^2+b^2+c^2=49 and ab+bc+ca=36, show that a+b+c=11

Answer 1

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

=49+2(ab+bc+ca). {Given a²+b²+c²=49

=49 + 2×36. {Given ab+bc+ca=36}

=49+72=121

√(a+b+c)²=√121

a+b+c=11

Answer 2

Answer:

see the attachment....

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