If a^2 + b^2+c^2 = 64 and ab+bc+ca=18. Find a+b+c.
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Answer:
(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab +2ac + 2bc
=64+2(ab+ac+bc)
=64+2×18
=64+36
=100
Therefore,
a+b+c=10
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