Math, asked by hemantkumarrai605, 5 months ago

If a^2 + b^2+c^2 = 64 and ab+bc+ca=18. Find a+b+c.​

Answers

Answered by srudhikm
4

Answer:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab +2ac + 2bc

=64+2(ab+ac+bc)

=64+2×18

=64+36

=100

Therefore,

a+b+c=10

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