Math, asked by yadavshersingh1109, 5 hours ago

if a^2+b^2+c^2=90,a+b+c=20 then find the vale of ab+bc+ca.​

Answers

Answered by AryanChauhan888
1

wait until the questions is solved

Answered by misscutie94
2

Answer:

Given :-

  • a² + b² + c² = 90
  • a + b + c = 20

Find Out :-

  • ab + bc + ca

Solution :-

we know,

➪ (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

➭ (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

➭ (20)² = 90 + 2(ab + bc + ca)

➭ 400 = 90 + 2(ab + bc + ca)

➭ 400 - 90 = 2(ab + bc + ca)

➭ 310 = 2(ab + bc + ca)

➭ ab + bc + ca = 310/2

➭ ab + bc + ca = 155

∴ The value of ab + bc + ca is 155

Similar questions