Question

if a^2+b^2+c^2= 90 and a+b+c = 20 then value of b+bc+ca is?

Answer 1

Answer:

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Given that,

• a² + b² + c² = 90
• a + b + c = 20
• ab + bc + ac = ?

✒ (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

➡ (20)² = 90 + 2(ab + bc + ac)

➡ 400 = 90 + 2(ab + bc + ac)

➡ 400 - 90 = 2(ab + bc + ac)

➡ 310 = 2(ab + bc + ac)

➡ (ab + bc + ac) = 310/2

➡ (ab + bc + ac) = 155

Therefore, the value of (ab + bc + ac) is “ 155 ”

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Step-by-step explanation:

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Answer 2

Answer:

Given that,

a² + b² + c² = 90

a + b + c = 20

ab + bc + ac = ?

✒ (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

➡ (20)² = 90 + 2(ab + bc + ac)

➡ 400 = 90 + 2(ab + bc + ac)

➡ 400 - 90 = 2(ab + bc + ac)

➡ 310 = 2(ab + bc + ac)

➡ (ab + bc + ac) = 310/2

➡ (ab + bc + ac) = 155

Therefore, the value of (ab + bc + ac) is “ 155 ”

Step-by-step explanation:

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