if a^2+b^2+c^2 =90 and a+b+c= 20 what is ab+bc+cd?
Answers
Answered by
1
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a+ b + c)2 = a2 + b2 + c2+ 2 (ab + bc + ca)
(20)2 = 90 + 2 (ab + bc + ca)
400 - 90 = 2 (ab + bc + ca)
ab + bc + ca = 155
Hope it helps
Thanks
Mark me as brainliest
(a+ b + c)2 = a2 + b2 + c2+ 2 (ab + bc + ca)
(20)2 = 90 + 2 (ab + bc + ca)
400 - 90 = 2 (ab + bc + ca)
ab + bc + ca = 155
Hope it helps
Thanks
Mark me as brainliest
Answered by
1
Answer:
155 is the answer . by using (a+b+c)^2
Similar questions