Question

if a^2+b^2+c^2=ab+bc+ca, then a+c:b=?​

Answer 1

Answer:

((a^2+c^2-ca)/b^2) + 1

Step-by-step explanation:

Given: a²+b²+c² = ab+bc+ca  

Dividing both sides with b²

⇒ (a²/b²)+1+(c²/b²) = ((a+c)/b)+(ca/b²)

((a+c)/b) = ((a²+c²-ca)/b²)+1

Therefore: (a+c):b = ((a²+c²-ca)/b²)+1         ans.

Answer 2

Answer:

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