If a^2 - b^2 is a prime number show that a^2-b^2=a+b,where a,b are natural numbers
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Hey buddy, You have typed a wrong question.....
It is not possible......
Answered by
1
Answer:
Step-by-step explanation:
u CANNOT assume the a^2 - b^2 is a prime number since a^2 - b^2 = (a - b)(a + b) is clearly a composite number
vivekpremnair:
1^2 - 2^2
= -3 and -3 is not a prime number
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