Question

if a^2 + b^2 = z and ab = y which evaluate to 4z + 8y​

Answer 1

Answer:

$\large\boxed{\sf{{\big[2(a+b)\big]}^{2}}}$

Step-by-step explanation:

It's given that,

${a}^{2} + {b}^{2} = z$

and also given that,

$ab = y$

Therefore, we have,

$= > 4z + 8y = 4( {a}^{2} + {b}^{2} ) + 8(ab) \\ \\ = > 4z + 8y = 4( {a}^{2} + {b}^{2} + 2ab) \\ \\ = > 4z + 8y = 4 {(a + b)}^{2} \\ \\ = > 4z + 8y = {\left[2(a + b)\right]}^{2}$

Concept Map :-

• ${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$