Question

if a√2+b = 3√2+4 , find the integral values of a and b and justify your answer​

Answer 1

Given:

$a\sqrt{2} +b = 3\sqrt{2}+4$

Find:

values of a and b

Answer:

$a=3\\b=4$

Step-by-step explanation:

     $a\sqrt{2} +b = 3\sqrt{2}+4$

compare

$a\sqrt{2} =3\sqrt{2}\\a=3$

$b=4$

Hence $a\sqrt{2} +b = 3\sqrt{2}+4$ then the integral values of a and b are 3 and 4.

#SPJ2

Answer 2

Answer:

$a=3,b=4$

Step-by-step explanation:

TO FIND: The integral values of a and b

GIVEN:

$a\sqrt{2} +b=3\sqrt{2} +4$

$a\sqrt{2}= 3\sqrt{2} ,b=4$

$a= \frac{3\sqrt{2}}{\sqrt{2} }$

$a=3,b=4$

The integral values of a and b $a=3,b=4$

The project code is #SPJ3