Question

If a=2,b=3√3+2√2 then​

Answer 1

Answer:

=3–√+2–√3–√−2–√

=(3–√+2–√)(3–√+2–√)(3–√−2–√)(3–√+2–√)

=(3–√+2–√)23−2

=((3–√)2+(2–√)2+2(3–√)(2–√)

=3+2+26–√

=5+26–√

Step-by-step explanation:

example sum

Answer 2

Step-by-step explanation:

$a = 2 \: \: \: b = 3 \sqrt{3} + 2 \sqrt{2} \\ squaring \: on \: both \: sides \\ {a}^{2} = {2}^{2} \\ {a }^{2} = 4 \\ {b}^{2} = (3 \sqrt{3} + 2 \sqrt{2} )^2 \\ {b}^{2} = 35 + 12 \sqrt{6} \\ clerly \: \: {b}^{2} > {a}^{2} \\ = > \: b > a \\ = > \: a < b$

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