Question

If a = 2,b=3 and c=-2 , find the value of :- a2 +b2 +c2 -2ab -2bc - 2ca +3abc

With full process I want !!plz

Answer is -11



...plz do it fast

Answer 1

$a {}^{2} + b { }^{2} + c {}^{2} - 2ab - 2bc - 2ca + 3abc$

Putting value of a,b, and c

$2 {}^{2} + 3 {}^{2} + ( - 2) {}^{2} - 2 \times 2 \times 3 - 2 \times 3 \times ( - 2) - 2 \times ( - 2) \times 2 + 3 \times 2 \times 3 \times ( - 2)$

= 4+9+4-12+12+8-36
= -11

Answer 2

$a^2+b^2+c^2-2ab-2bc-2ca+3ab=-11$

Step-by-step explanation:

Given : Expression $a^2+b^2+c^2-2ab-2bc-2ca+3abc$ If a = 2,b=3 and c=-2.

To find : The value of the expression ?

Solution :

Expression $a^2+b^2+c^2-2ab-2bc-2ca+3abc$

Substitute, a = 2,b=3 and c=-2.

$=2 {}^{2} + 3 {}^{2} + ( - 2) {}^{2} - 2 \times 2 \times 3 - 2 \times 3 \times ( - 2) - 2 \times ( - 2) \times 2 + 3 \times 2 \times 3 \times ( - 2)$

$= 4+9+4-12+12+8-36$

$=-11$

Therefore, $a^2+b^2+c^2-2ab-2bc-2ca+3ab=-11$

#Learn more

If a:b = c:d = e:f = 2:3 then find the value of (a+c+e)/(b+d+f)​

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