Math, asked by ankitraj4315, 2 months ago

if a=-2,b=-3 and c=5 find the value of:2a+3b-5c-a^2-b^2+c^2​

Answers

Answered by 612005pawan
0

Step-by-step explanation:

if a=-2,b=-3 and c=5 find the value of:2a+3b-5c-a^2-b^2+c^2

put the value of a,b,c

2(-2)+3(-3)-5(5)-(-2)^2-(-3)^2+5^2

=0

Answered by vipinkumar212003
0

Step-by-step explanation:

a =  - 2, \: b=-3, \: and \: c=5 \\ 2a + 3b - 5c -  {a}^{2}  -  {b}^{2}  +  {c}^{2}  \\  = 2 \times ( - 2) + 3 \times ( - 3) - 5 \times 5 -  {( - 2)}^{2}  -  {( - 3)}^{2}  +  {(5)}^{2}  \\ =   - 4 - 9 - 25 - 4 - 9 + 25 \\  =  - 26

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