Question

If a=2,b=3,c=1 , find the value of:
1)
${a}^{3} + (b + c {)}^{3}$

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Answer 1

Here an equation is given $a^{3} + ( b + c )^{3}$

Taking a cube of a number means we have to multiply the number to itself 3 times.

We are given the values of a, b, and c

a = 2, b=3, c=1

So, we will substitute the given values in the equation

$a^{3} + ( b + c )^{3} = 2^{3} + ( 3 + 1 )^{3}$

                    $= 8 +4^{3}$

                    = 8 + 64

                    = 72

Therefore, the answer will be 72

Answer 2

Given: The values of$a,b,and c$ are$a=2,b=3, and c=1$.

We have to find the value of$a^{3}+(b+c)^{3}$.

By putting the values given values that are$a=2,b=3, and c=1$ in the equation, we are finding the value of the given equation.

We are solving in the following way:

We have,

$a^{3}+(b+c)^{3}$

$=>2^{3} +(3+1)^{3} \\=>8+(4)^{3}\\=>8+64$

Solving the above equation further we get,

$=>72$

Hence, after solving the given equation the solution of the equation will be$72$.