Question

If a = 2 , b= -3 , c=2 , find the value of 4ab²- 3bc²+4a²c​

Answer 1

Answer:

4

Step-by-step explanation:

4*2(3)²-(3)²(2)²+4*(2)³

72-36+32

72-68

4

Answer 2

Answer:

Given that,

a = 2, b = -3, c = 2

4ab square - 3bc square + 4a square c

4 [2] [-3] square - 3 [-3] [2] square + 4 [2] square [2]

4 [2] [9] - 3[-3] [4] + 4 [4] [2]

4 [18] - 3 [-12] + 4 [8]

72 - [-15] + 32

72 + 15 + 32 = 119