Question

if a= ‐2, b= ‐3 c= ‐4 then find the value of a³ + b³–4abc​

Answer 1

Answer:

61

Step-by-step explanation:

Given :

a = -2

b = -3

c = -4

To Find:

a³ + b³ -4abc

Procedure:

>> Let's start by ploughing the given values to equation.

$\sf \implies (-2)^3 + (-3)^3 -4(-2)(-3)(-4)$

$\implies \sf (-8)+(-27)-(4)(-2)(-3)(-4)$

$\implies \sf(-35)-(4)(-2)(-3)(-4)$

$\implies \sf (-35)-((-8)(-3))(-4)$

$\implies \sf -(35)-(24)(-4)$

$\implies \sf (-35)-(-96)$

$\implies \sf (-35)-(-96)$

$\implies \sf 61$

Important Points to Note:-

• Polynomial : A variable bases language in maths. or A string of variables and numbers put together.

• Degree of polynomial : Highest power of a polynomial is called degree of polynomial.

• Coefficient : A number by which a variable is multiplied.

• Constant : It's a numerical term holding no variable.

Answer 2

AnswEr :

• 61

Given :

• a = - 2
• b = - 3
• c = - 4

To Find :

• The value of a³ + b³ - 4abc

SoluTion :

Put the values of a , b and c in the equation

According to question :

(- 2)³ + (- 3)³ - { 4 (-2) (-3) (-4) }

→ (- 8) + (- 27) - { (-8) (12) }

→ (- 8) + (- 27) - {- 96}

→ (-35) + 96

→ 61

Hence, the value of a³ + b³ - 4abc is 61.

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