Question

If a^2 = b^3 = c^5 = d^6, show that log base d abc = 31/5​

Answer 1

$\huge{\boxed{\mathtt{\red{ANSWER}}}}$

a^2 = b^3 = c^5 = d^6

a² = d^6

a = (d^6)^1/2

similarly , b = (d^6)^1/3 &. c = (d^6)^1/5

putting in log(base d)(abc) = logd[(d^6)^1/2*(d^6)^1/3*(d^6)^1/5]

= logd[ d^6] ^ 31/30

= logd[d]^31/5

= 31/5logd[d]

( according of log base rule we know that logd[d] = 1]

= 31/5 (Ans)

$\huge{\boxed{\mathtt{\red{Mark\: As\: Brainlist}}}}$