If a=2, b=3, c=5 Find :- ( \alpha + \beta )^{2}(α+β)2
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\begin{gathered} \alpha \: and \: \beta \: are \: zeroes \: of \: x ^{2} - x - 1 \: find \: \\ \alpha + \beta \\ \alpha ^{2} + \beta ^{2} \\ \alpha \times \beta \ \\ \binom{ \alpha }{ \beta } + \binom{ \beta }{ \alpha } \\ \alpha - \beta \end{gathered}
αandβarezeroesofx
2
−x−1 find
α+βα 2 +β 2
α×β(βα)+(αβ)α−β
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Answer:
2
-x-1 find
a+Ba 2+ß 2 axß(Ba)+(ap)a-ß
Explanation:
may it's helps you
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