Question

if a=2, b=3, find the value of (a^a+b^b)^-1

Answer 1

(2^2+3^3)^-1
(4+27)^-1
1÷31 may be the answer

Answer 2

Answer:

Given that

a = 2 ; b = 3

(a^b + b^a)^ -1

= (2^3 + 3^2)^ - 1

= (8 + 9)^-1

= (17)^ -1

= 1/17

Thanks