Question

if a=2,b=3,find the value of
(a^a+ b^b)^-1

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Answer 1

Answer:

$\huge\underline\bold\pink{Answer}$

$(a ^{a} + b^{b} ) ^{ - 1} \\ putting \: the \: value \: a = 2 \: \: \: \: \: \: \: b = 3 \\ (2 ^{2} + {3}^{2} )^{ - 1} \\ (4+ 27) ^{ - 1} \\ 31^{ - 1} \\ \frac{1}{31}$

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Answer 2

Answer:

a = 2 and b = 3

Now,

         i) (a^a + b^b)^-1

           = (2^2 + 3^3)^-1

           = (4 + 9)^-1

           = 13^-1

           = 1/13

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