if a=2,b=-3,verify that (×+y)3=×3+y3+3×2y+3×y2
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Answer:As given a=2,b=-3
LHS is (x+y)^3=(2+(-3))^3=(-1)^3=-1
RHS is x^3+y^3+3x^2y+3xy^2
=2^3+(-3)^3+3×2^2×(-3)+3×2×(-3)^2
=8+(-27)-36+54=62-63=-1
As LHS=RHS (PROVED)
Step-by-step explanation:
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