Question

IF a=-2,b=-3andc=5, THEN FIND THE VALUE OF :
(i)ab2+bc2+ca2+ab+bc+ca+2abc​

Answer 1

Answer:

ab²+bc²+ca²+ab+bc+ca+2abc

→if a=-2,b=-3andc=5

=(-2)(-3)²+(-3)(-2)²+(5)(-2)²+(-2)(-3)+(-3)(5)+(5)(-2)+2(-2)(-3)(5)

→(-18)+(-12)+(20)+(6)+(-15)+ (-10)+(60)

→ 31

Answer 2

Answer:

Ans: 9

Step-by-step explanation:

a=-2, b=-3 and c=5

then a+b+c=-2-3+5=0

ab²+bc²+ca²+ab+bc+ca+2abc​

=ab2+bc2++2abc​ +ab+bc+ca+ca2

=a( b²+2bc+c²)+b(a+c)+ca+ca²

=a(b+c)²+b(a+b+c-b) +ca+ca²

=a(-a)²+b(-b)+ca+ca²

=-a³-b²+ca+ca²

=ca²-a³+ca-b²

=a²(c-a) +ca-b²

Put values of a, b and c

=(-2)²(5+2)+(5)(-2)-(-3)²

=4*7-10-9

=28-19

=9