Question

If |A| =2, |B|=5 and |AXB|=8 and if angle between A and B is acute, then A.B is:
a. 6 b.3 c.4 d.7

Answer 1

Answer: answer is option A (6).

Explanation:

Answer 2

Answer:

a.6

Explanation:

|AXB|=ABsinα

Hence 8=2x5xsinα

            Hence sinα=4/5

               As this is a 3,4,5 triangle we can say cosα=3/5

And A.B is AxBxcosα and hence this is 2x5x3/5 which is 6

PLZ mark as branliest