if a^2+b&2=100, ab=8 find the value of a+b
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Answered by
1
Answer:
Given:
a2 + b2 = 100
ab = 48
We know that,
82 + 62 = 100
Now putting these two value in second condition,
⇒ 8 × 6 = 48
For both condition values 8 and 6 satisfy.
⇒ a = 8 and b = 6
Putting the values in asked form, we get
(a + b)/(a - b) = (8 + 6)/(8 – 6)
⇒ (a + b)/(a - b) = 14/2
⇒ (a + b)/(a - b) = 7
∴ The value of (a + b)/(a - b) is 7.
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Answered by
4
Answer:
Value of (a+b)/(a-b) is 7
this is your correct answer
Explanation
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