Question

if A + 2 b + c equal to zero then show that a cube + 8 b cube plus c cube equal to 6 ABC

Answer 1

Answer:

Proved below.

Step-by-step explanation:

Given,

    a + 2b + c = 0

⇒ a + 2b + c = 0

⇒ a + 2b = - c

Cubing on both sides :

⇒ ( a + 2b )^3 = ( - c )^3

⇒ a^3 + ( 2b )^3 + 3( a + 2b )( a x 2b )  = - c^3

⇒ a^3 + 8b^3 + 3( - c )( 2ab ) = - c^3         { a + 2b = - c }

⇒ a^3 + 8b^3 - 6abc = - c^3

⇒ a^3 + 8b^3 + c^3 = 6abc

   Hence proved.

Answer 2

Answer:

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Step-by-step explanation:

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