If a=2ỉ + j and b=3i+4j and c = 2i +5j, then find a. (b+c)
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if →a=i+2j+k,→b= 2i+j and →c=3i-4j-5k, then find a unit vector perpendicular to both of the vectors (→a-→b) ...
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Answer: Here, a=2ỉ + j and b=3i+4j and c = 2i +5j
To find : a . (b+c)
Then, a.(b+c) = ab +ac = ( 2i +j) ( 3i +4j) + (2i +j ) ( 2i + 5j)
= 6 +4+ 4 + 5
= 19 ans
Explanation: Here, i have done on the basis of the dot product .It gives that [ i . i = 1 , i . j = 0 ]
[ j . j =1 , j . i =0 ]
so by factorizing then we can multiply it by dot product.
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