if [a =π/{(2 ^n ) + 1)]prove that [(2^n) cos a cos 2a cos 2²a cos 2³a. cos (2^n) - 1] = 1
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Answered by
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Answer:
LHS=(
2sinA
2sinAcosAcos2Acos4Acos8A
)
=(
2×2sinA
2×sin2Acos2Acos4Acos8A
)
=(
2×4sinA
2×sin4Acos4Acos8A
)
=(
2×8sinA
2×sin8Acos8A
)
=(
16sinA
sin16A
)=RHS
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