If a, = √2 n+ √6 represents the nth term of an A.P., then common difference is equal to:
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The common difference is root2
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Step-by-step explanation:
if a=√2 n+ √6
then,
√2 n+ √6=first term,
then,
tn=√2 n+ √6 +(n-1)d (tn=a+(n-1)d)
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