If a=2+root3, then a square+1/a
square
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=> a = 2+√3 ...(1)
=> 1/a = 1/2+√3
By rationalization,
=> 1/a = 1/(2 + √3) × (2 - √3)/(2 - √3)
=> 1/a = (2 - √3)/(2 + √3)(2 - √3)
=> 1/a = (2 - √3)/(2² - √3²)
=> 1/a = 2 - √3
Now,
=> a²+1/a²
=> (2+√3)²+(2-√3)²
=> 4+3+4√3 +4+3-4√3
=> 4+3+4+3
=> 14
Hope it will help
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