If
a
2
then
f
b
5
el
1
a2
62
2
2) 2a?
36²
е e
3) a
2
4) 2a²+36²
2 a ² – 36²
Answers
Answered by
0
Answer:
We have,
a
2
,b
2
,c
2
are in A.P
⇒b
2
−a
2
=c
2
−b
2
⇒(b−a)(b+a)=(c−b)(c+b)
⇒
(c+b)
(b−a)
=
(b+a)
(c−b)
⇒
(c+b)(c+a)
(b−a)
=
(b+a)(c+a)
(c−b)
⇒
(c+b)(c+a)
(b+c−c−a)
=
(b+a)(c+a)
(c+a−a−b)
⇒
c+a
1
−
b+c
1
=
a+b
1
−
c+a
1
b+c
1
,
c+a
1
,
a+b
1
are in A.P
b+c
a+b+c
,
c+a
a+b+c
,
a+b
a+b+c
are in A.P
b+c
a
+1,
c+a
b
+1,
a+b
c
+1 are in A.P
b+c
a
,
c+a
b
,
a+b
c
are in A.P
Hence, this is the answer.
Step-by-step explanation:
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