Math, asked by Ayeshatamboli1305, 4 months ago

If
a
2
then
f
b
5
el
1
a2
62
2
2) 2a?
36²
е e
3) a
2
4) 2a²+36²
2 a ² – 36²​

Answers

Answered by subhsamavartj
0

Answer:

We have,

a  

2

,b  

2

,c  

2

 are in A.P

⇒b  

2

−a  

2

=c  

2

−b  

2

 

⇒(b−a)(b+a)=(c−b)(c+b)

⇒  

(c+b)

(b−a)

​  

=  

(b+a)

(c−b)

​  

 

⇒  

(c+b)(c+a)

(b−a)

​  

=  

(b+a)(c+a)

(c−b)

​  

 

⇒  

(c+b)(c+a)

(b+c−c−a)

​  

=  

(b+a)(c+a)

(c+a−a−b)

​  

 

⇒  

c+a

1

​  

−  

b+c

1

​  

=  

a+b

1

​  

−  

c+a

1

​  

 

b+c

1

​  

,  

c+a

1

​  

,  

a+b

1

​  

 are in A.P

b+c

a+b+c

​  

,  

c+a

a+b+c

​  

,  

a+b

a+b+c

​  

 are in A.P

b+c

a

​  

+1,  

c+a

b

​  

+1,  

a+b

c

​  

+1 are in A.P

b+c

a

​  

,  

c+a

b

​  

,  

a+b

c

​  

 are in A.P

Hence, this is the answer.

Step-by-step explanation:

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