Question

if A=20
(3 sin 3A + 2 cos (2A+5))/(2 cos 3A-sin (2A-10))​

Answer 1

Answer:

(3sin 3A + 2cos(2A+5))/(2cos 3A - sin(2A-10))

A= 20 (given)

(3sin 90 +2cos(45))/(2cos60- sin(30))

Step-by-step explanation:

$(3 \times 1 + \sqrt{2} ) \: \div (1 \div 2 \times 2 - 1 \div 2 \\ (3 + \sqrt{2} ) \: \: \div (1 - 1 \div 2) \\ ( 3 + \sqrt{2} ) \div (1 \div 2) \\ (3 + \sqrt{2} ) \: \: \times 2 = 6 + 2 \sqrt{2}$

Answer 2

Answer:

3 sin 3*20 + 2 cos (2*20+5)/2cos 3*20-sin (2*20-10)

= 3 sin 60° +2 cos 45° / 2 cos 60°-sin 30°

= 3*√3/2+2*1√2 / 2* 1/2 -1/2

=3√3/2+2√2 ÷ 2-1/2

= 3√3√2/2√2÷1/2

=3√3√2/2√2*2/1

=3√3 + 2√2