Question

If A = 20°, evaluate
3 sin3A +2cos (2A +5°)/2cos3A-sin(2A-10°)​

Answer 1

Answer:

$3 \sqrt{3 } + 2 \sqrt{2}$

Step-by-step explanation:

When you substitute the value of A in the equation you get

$((3 \times \sin(60) ) + (2 \times \cos(45) ) \div ((2 \times \cos(60)) - ( \sin(30) ))$

Substitute the value for sin and cos as follows

Sin 60 = (root(3))/2

Cos 45 = 1/(root (2))

Cos 60 = 1/2

Sin 30 = 1/2