Physics, asked by crazycop007, 9 months ago

if a 200 newton force is acting in the block of dimensions 20 cm x 10 cm x 5 cm , find the maximum and minimum pressure exerted by the sides of the block

Answers

Answered by sonuvuce
2

Maximum pressure exerted by the force is 40000 N/m²

Minimum pressure exerted by the force is 10000 N/m²

Explanation:

Given:

Dimensions of the block = 20 cm × 10 cm × 5 cm

And a 200 N force is applied

To find out:

The maximum and minimum pressure exerted by the force on the sides of the block

Solution:

There will be 6 surfaces of the block

With two surface each of area = 20 cm x 10 cm = 200 cm²

Other two surfaces each of area = 10 cm x 5 cm = 50 cm²

Last two surfaces each of area = 20 cm x 5 cm = 100 cm²

As we know that

\text{Pressure}=\frac{\text{Force}}{\text{Contact Area}}

i.e. pressure is inversely proportional to the area

Thus,

The pressure will be maximum when area is minimum

And, the pressure will be minimum when the area is maximum

Here the minimum area is 50 cm² and the maximum area is 200 cm²

Therefore,

The maximum pressure is

P=\frac{200}{50\times 10^{-4}} N/m²

\implies P=4\times 10^4 N/m²

\implies P=40000 N/m²

The minimum pressure is

P=\frac{200}{200\times 10^{-4}} N/m²

\implies P=1\times 10^4 N/m²

\implies P=10000 N/m²

Hope this answer is helpful.

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Answered by Anonymous
0

Given:

Newton force = 200N

Dimensions of block = 20 cm x 10 cm x 5 cm

To Find:

Maximum and minimum pressure exerted by the sides of the block

Solution:

Let the pressures exerted by the brick while resting on different faces be = P1, P2 and P3.

Case (i) : When the block is resting on 20cm × 10cm face.

F = 200 N

= 20 /200  x 10 / 200  

= .005 m²

Pressure = Force /Area

= 200 / .005

 = 40,000 pa

Case (ii) : When the block is resting on 20cm × 5cm face

F = 200 N

Area = 20 cm x 5cm  

20 /200 m x 5/ 200 m

= .0025 m²

Pressure = Force /Area

= 200 / .0025

= 80,000 pa

Case (iii) : When the block on 10cm×5cmface

F = 200 N

= 10 /200  x 5 / 200  

= .00125 m²

Pressure = Force /Area

= 200 / .00125

= 1,60,000 pa

Answer: the maximum pressure is 1,60,000 pa and the minimum pressure is 40,000 pa

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