if a=2021,b= -1016 and c= -1005,then the value of (a^4/b+c)+(b^4/c+a)+(c^4/a+b)+3abc=??
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Answer:
Ans. = 2012(2012-2011)+2011(2011-2010+2010(2010-2012)
= 2012*1+2011*1+2010(-2)
= 2012+2011-4020
= 4023 - 4020
= 3.
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