If a=23, b=27 and c=-50 then the value of a3+b3-c3+3abc is
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Answered by
0
Answer:
= a cube + b cube + c cube
= 23 cube + 27 cube + -50 cube
= 12167+ 19683-12500
= - 29350
Answered by
0
Step-by-step explanation:
Consider the expression a
3
+b
3
−c
3
+3abc and substitute a=23,b=27 and c=50 as shown below:
a
3
+b
3
−c
3
+3abc=(23)
3
+(27)
3
−(50)
3
+(3×23×27×50)=12167+19683−125000+93150
=(12167+19683+93150)−125000=125000−125000=0
Hence, a
3
+b
3
−c
3
+3abc=0
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