Math, asked by pinky65527, 1 month ago

If a= 2³ x 3 , b= 2x3x5, c= n x 5 , and LCM (a,b,c)= 2³ x 3² x 5, then n=

Answers

Answered by kaushalthakur867
11

Answer:

Correct question is:

if a = 2*3, b = 2*3*5, c = 3n *5 and the LCM (a,b,c)= 2 * 3 * 3 * 5

Then find the value of n?

Solution:

Given,

a = 2 * 3

b = 2 * 3 * 5

c = 3n * 5

Now, LCM (a,b,c) = 2 * 3 * 3 * 5

=> 2 * 3n * 5 = 2 * 3 * 3 * 5

=> 2 * 3n * 5 = 2 * 32 * 5

=> n = 2

Answered by aryanagarwal466
2

Answer:

The value of n=2.

Step-by-step explanation:

It is given that:

a = 2*3

b = 2*3*5

c = 3n *5

Also,

LCM (a,b,c)= 2 * 3 * 3 * 5

We need to determine value of n.

From given data, LCM has to be

2 * 3n * 5

LCM given is 2 * 3 * 3 * 5

Equating,

2 * 3n * 5 = 2 * 3 * 3 * 5

2 * 3n * 5 = 2 * 32 * 5

n=2

#SPJ3

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