If a=234, b=c=233 then find a³+b³+c³-3abc
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Answered by
0
b = c = 233 is it so then
your ans is 9700
steps
=12812904+12649337+12649337-(38110878)
=38111578-38110878
=9700
your ans is 9700
steps
=12812904+12649337+12649337-(38110878)
=38111578-38110878
=9700
Answered by
0
Here a-b=1
a-b=1
&b-c=0
Therefore a^3+b^3+c^3-3×abc=a+b+c
Hence a^3+b^3+c^3-3×ab=234+233+233
=700
a-b=1
&b-c=0
Therefore a^3+b^3+c^3-3×abc=a+b+c
Hence a^3+b^3+c^3-3×ab=234+233+233
=700
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