If A=24 P²-QS4and B=108PQ
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Step-by-step explanation:
See what you can do is try and make perfect squares. So if you add 4 on lhs and rhs you get (p+2)^2,similarly add 16 and 25 on both sides so you will get( q+4)^2 and (r+5)^2 on lhs. After adding4+16+25 you get 45 on rhs. So that balances the - 45 and you get a zero on rhs. Now sum of three perfect squares is equal to 0 only when all of them are 0.hence p=-2,q=-4,r=-5.And you get the required answer.
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