If A + 25° is an acute angles such that Sin (A + 25°)= cos 35°, find A.
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4
given: A+25 degree is an acute angle
Sin(A+25)=Cos35 (given)
solution:
Sin(A+25)=Cos35
Sin90-(A+25)=cos35
cos(A+25)=cos35
comparing both sides
A+25=35
A=10
hence value of A is 10
Note: sin (90-¤)=cos¤ [¤-represebts theta)
cos(90-¤)=sin¤
tan(90-¤)=cot¤
cot(90-¤)=tan¤
sec(90-¤)=cosec¤
cosec(90-¤)=sec¤
Answered by
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See the attachment which I attached .
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