Math, asked by Shrikrishan789, 1 year ago

If a−2b=15 and ab=11 then find the value of a2+4b2?

Answers

Answered by 8334812253shinam
4

SBS

(a-2b)^2=15×15

a^2+4b^2-4ab=225

a^2+4b^2-4*11=225

a^2+4b^2=225+44

a^2+4b^2=269

Answered by aakankshabtsarmy
4

a²+4b²=269

Explanation:

(a-2b)²= a²-4ab+4b²=15²

a²+4b²=15²+4ab=15²+4×11=269

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