if a+2b+3c=0 prove a3 +8b3+27c3=18abc
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a+2b+3c=0 then
a+2b=-3c
(a+2b)3=(-3c)3 (By cubing)
a3+(2b)3+3(a)(2b)(a+2b) = -27c3
a3+8b3+6ab (-3c) = -27c3 [a+2b=-3c]
a3+8b3-18abc = -27c3
a3+8b3+27c3 = 18abc
Hence proved...
Hope it will help uh dud...
a+2b=-3c
(a+2b)3=(-3c)3 (By cubing)
a3+(2b)3+3(a)(2b)(a+2b) = -27c3
a3+8b3+6ab (-3c) = -27c3 [a+2b=-3c]
a3+8b3-18abc = -27c3
a3+8b3+27c3 = 18abc
Hence proved...
Hope it will help uh dud...
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34
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